∏n=215n15=2⋅3⋅4…151514product from n equals 2 to 15 of n over 15 end-fraction equals the fraction with numerator 2 center dot 3 center dot 4 … 15 and denominator 15 to the 14th power end-fraction 4. Simplify with factorials The numerator is (15 factorial) excluding , the numerator is simply .The denominator is 151415 to the 14th power because there are 14 terms (from ).The formula becomes:
The product of the sequence is approximately 1. Identify sequence pattern (2/15)(3/15)(4/15)(5/15)(6/15)(7/15)(8/15)(9/15...
15!1514the fraction with numerator 15 exclamation mark and denominator 15 to the 14th power end-fraction , which equals approximately which equals approximately